Math & ScienceAny two inputs

Ohm's Law Calculator

Ohm's law ties voltage, current and resistance together, and the power formula adds watts. Give this any two of the four and it derives the rest — which is exactly how the law is used in practice, because you can almost never measure all four.

Fill In Any Two

Leave the other two blank. Exactly two values are needed — no more, no less.

Potential difference
V
Leave blank if unknown
A
Ω
W
RESULT
6 Ω · 24 W
Voltage (V)12 V
Current (I)2 A
Resistance (R)6 Ω
Power (P)24 W
Energy if run for 1 hour0.024 kWh
From V and I: R = 6 Ω, P = 24 W. Run continuously for an hour that load uses 0.024 kWh. These formulas assume an ohmic load at steady temperature — a filament lamp, motor or semiconductor will not obey them across its operating range.

The two formulas underneath

Ohm's law states that current through a conductor is proportional to the voltage across it and inversely proportional to its resistance: V = I × R. The power formula is separate and older: P = V × I. Combine them by substitution and you get the familiar variants — P = I²R and P = V²/R — which is why any two of the four quantities fix the other two. That is the whole trick behind this calculator, and behind the Ohm's law wheel printed in the back of electronics textbooks.

Why exactly two values

One value is not enough: a 12 V supply says nothing about current until something is connected. Three or four is over-determined — if you enter values that contradict each other there is no correct answer, only a choice of which input to ignore. Silently picking one would hide your mistake, so this tool asks for exactly two and tells you when you have given it more. If your four measured values disagree, that disagreement is the finding: either a meter is wrong or the circuit is not what you think it is.

Where the law stops working

Ohm's law describes ohmic materials — metals and carbon resistors at steady temperature. Diodes, transistors, fluorescent lamps and most semiconductors are non-ohmic: their resistance changes with the voltage applied, so a single R does not describe them. Incandescent bulbs are a classic trap, because a cold filament has a fraction of its hot resistance, which is why they draw a large inrush current at switch-on. Batteries have internal resistance, so terminal voltage sags under load.

AC is a different question

Everything above is direct current. In alternating-current circuits, capacitance and inductance add reactance, and the quantity that opposes current is impedance (Z), not plain resistance. Voltage and current can also fall out of step, so real power in watts is no longer simply volts times amps — it is volts times amps times the power factor. For a purely resistive AC load such as a heating element, the power factor is 1 and these formulas hold with RMS values. For motors, transformers and switch-mode supplies it does not, and using the DC formula will overstate the real power consumed.

Reading the energy line

Power is a rate; energy is power multiplied by time. The last output line converts watts into the kilowatt-hours you would be billed for if the load ran continuously for an hour, which is often the number you actually care about. A 60 W lamp left on all day is 1.44 kWh; multiply by your tariff to price it.

Frequently Asked Questions

Can I enter all four values?
No, and that is deliberate. Four values are over-determined: if they disagree, the calculator would have to ignore one of your measurements without telling you. Enter the two you trust and compare the derived pair against what you measured.
Why does my bulb draw more current than this predicts?
Filament lamps are not ohmic. A cold tungsten filament has roughly a tenth of its hot resistance, so the inrush current at switch-on is far higher than the steady-state figure. The same applies to motors starting under load.
Does this work for AC circuits?
Only for purely resistive AC loads such as heaters, using RMS voltage and current. Anything with a motor, transformer or electronic supply has reactance and a power factor below 1, so watts are less than volts times amps.
What is the kWh line for?
It converts the calculated power into energy consumed over one hour, which is the unit utilities bill in. Multiply by hours of use and by your rate per kWh to get a running cost.
Where these numbers come from

Sources

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